3(x-3)^2+x^2=x(x+61)-49x

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Solution for 3(x-3)^2+x^2=x(x+61)-49x equation: 



3(x-3)^2+x^2=x(x+61)-49x

We move all terms to the left:

3(x-3)^2+x^2-(x(x+61)-49x)=0



We calculate terms in parentheses: -(x(x+61)-49x), so:

x(x+61)-49x

We add all the numbers together, and all the variables

-49x+x(x+61)

We multiply parentheses

x^2-49x+61x

We add all the numbers together, and all the variables

x^2+12x

Back to the equation:

-(x^2+12x)



We get rid of parentheses

x^2-x^2+3(x-3)^2-12x=0

We add all the numbers together, and all the variables

-12x+3(x-3)^2=0

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